Advertisements
Advertisements
Question
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From point P, draw a perpendicular to AB.
Advertisements
Solution
Step of Construction :
- Draw a line segment AB = 5.5 cm
- With A as centre and radius = 6 cm, draw an arc.
- With B as centre and radius = 4.8 cm draw another arc.
- Let these arcs meet each other at point P.
PA = 6 cm, PB = 4.8 - With P as a centre and some suitable radius draw an arc meeting AB at points C and D.
- With C as centre and radius more than half of CD, draw an arc.
- With D as a centre and same radius as in step 6, draw an arc.
- Let these arcs meet each other at point Q.
- Join PQ.
- The PQ meet AB at point O.
Then PO ⊥ AB i.e; ∠AOP = 90° = ∠POB.
APPEARS IN
RELATED QUESTIONS
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
In each of the following, draw perpendicular through point P to the line segment AB :
(i)
(ii)
(iii)
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
5.6 cm
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
58 mm
Bisect a right angle, using ruler and compasses. Measure each part. Bisect each of these parts. What will be the measure of each of these parts?
Draw a line segment of length 10 cm. Divide it into four equal parts. Measure each of these parts.
Repeat Question 6, if `overline"AB"` happens to be a diameter.
Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `overline"OA"` and `overline"OB"`. Let them meet at P. Is PA = PB ?
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
What is the minimum compass opening required when constructing a perpendicular bisector of line segment AB?
