Advertisements
Advertisements
प्रश्न
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From point P, draw a perpendicular to AB.
Advertisements
उत्तर
Step of Construction :

- Draw a line segment AB = 5.5 cm
- With A as centre and radius = 6 cm, draw an arc.
- With B as centre and radius = 4.8 cm draw another arc.
- Let these arcs meet each other at point P.
PA = 6 cm, PB = 4.8 - With P as a centre and some suitable radius draw an arc meeting AB at points C and D.
- With C as centre and radius more than half of CD, draw an arc.
- With D as a centre and same radius as in step 6, draw an arc.
- Let these arcs meet each other at point Q.
- Join PQ.
- The PQ meet AB at point O.
Then PO ⊥ AB i.e; ∠AOP = 90° = ∠POB.
APPEARS IN
संबंधित प्रश्न
In each of the following, draw perpendicular through point P to the line segment AB :
(i)

(ii)

(iii)

Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
5.6 cm
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
58 mm
Infinitely many perpendiculars can be drawn to a given ray.
Draw a line segment of length 6.5 cm and divide it into four equal parts, using ruler and compasses.
Copy figure on your notebook and draw a perpendicular to l through P, using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendiculars are you able to draw?

Bisect ∠XYZ of figure.

Draw `overline"AB"` of length 7.3 cm and find its axis of symmetry.
With `overline"PQ"` of length 6.1 cm as diameter, draw a circle.
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
