Advertisements
Advertisements
प्रश्न
Draw a line segment AB = 6.2 cm. Mark a point P in AB such that BP = 4 cm. Through point P draw perpendicular to AB.
Advertisements
उत्तर
Steps of Construction :
- Draw a line segment AB = 6.2 cm
- Cut off BP = 4 cm
- With P as the centre and some radius draw arc meeting AB at the points C, D.
- With C, D as centres and equal radii [each is more than half of CD] draw two arcs, meeting each other at the point O.
- Join OP. Then OP is perpendicular for AB.

APPEARS IN
संबंधित प्रश्न
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
In each of the following, draw perpendicular through point P to the line segment AB :
(i)

(ii)

(iii)

It is possible to draw two bisectors of a given angle.
Copy figure on your notebook and draw a perpendicular from P to line m, using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendicular are you able to draw?

Bisect ∠XYZ of figure.

Draw a line segment of length 10 cm. Divide it into four equal parts. Measure each of these parts.
Draw a line segment of length 12.8 cm. Using compasses, divide it into four equal parts. Verify by actual measurement.
Draw any angle with vertex O. Take a point A on one of its arms and B on another such that OA = OB. Draw the perpendicular bisectors of `overline"OA"` and `overline"OB"`. Let them meet at P. Is PA = PB ?
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
If point X lies on the perpendicular bisector of segment AB, then:
