Advertisements
Advertisements
प्रश्न
Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From point P, draw a perpendicular to AB.
Advertisements
उत्तर
Step of Construction :

- Draw a line segment AB = 5.5 cm
- With A as centre and radius = 6 cm, draw an arc.
- With B as centre and radius = 4.8 cm draw another arc.
- Let these arcs meet each other at point P.
PA = 6 cm, PB = 4.8 - With P as a centre and some suitable radius draw an arc meeting AB at points C and D.
- With C as centre and radius more than half of CD, draw an arc.
- With D as a centre and same radius as in step 6, draw an arc.
- Let these arcs meet each other at point Q.
- Join PQ.
- The PQ meet AB at point O.
Then PO ⊥ AB i.e; ∠AOP = 90° = ∠POB.
APPEARS IN
संबंधित प्रश्न
Draw a line segment PQ = 4.8 cm. Construct the perpendicular bisector of PQ.
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
7 cm
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
58 mm
Draw an angle of 140° with the help of a protractor and bisect it using ruler and compasses.
Bisect ∠XYZ of figure.

Bisect a straight angle, using ruler and compasses. Measure each part.
Draw a circle with centre C and radius 3.4 cm. Draw any chord `overline"AB"`. Construct the perpendicular bisector of `overline"AB"` and examine if it passes through C.
Draw a circle of radius 4 cm. Draw any two of its chords. Construct the perpendicular bisectors of these chords. Where do they meet?
Which two conditions, when combined, define the Perpendicular Bisector of a line segment AB?
If a line passes through the midpoint of segment AB but does not form a 90° angle, it is:
