English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Discuss the variation of conductivity and molar conductivity with concentration.

Advertisements
Advertisements

Question

Discuss the variation of conductivity and molar conductivity with concentration.

Very Long Answer
Advertisements

Solution

Both conductivity and molar conductivity change with changes in the concentration of the electrolyte. Conductivity always decreases as the concentration of both weak and strong electrolytes decreases. This can be explained by the fact that with dilution, the number of ions carrying electric current per unit volume decreases. The conductivity of a solution at any concentration is the conductivity of a unit volume of the solution placed between two platinum electrodes having a unit cross-sectional area and situated at a unit distance from each other.

This is clear from the following equation:

C = `(kappa A)/l` = κ  ...(Both A and l are in appropriate units m or cm)

The molar conductivity of a solution at a given concentration is the conductivity of volume (V) of the solution containing one mole of electrolyte dissolved in it and placed between two electrodes of cross-sectional area (A), located at a unit distance from each other. So,

Plot of c1/2 versus molar conductivity for potassium chloride (a strong electrolyte) in aqueous solution.

∧m = `(kappa A)/l` = κ

Since l = 1 and A = V (volume in which one mole of electrolyte is dissolved)

∧m = κ V

Molar conductivity increases with decreasing concentration. This is because the total volume (V) in which one mole of electrolyte is present also increases. It has been found that, upon dilution of the solution, the increase in volume is much greater than the decrease in κ.

Strong Electrolytes: For strong electrolytes, the value of ∧m increases gradually with dilution, and it can be represented by the following equation:

∧m = `Lambda_m^0 - Ac^(1//2)`

It can be seen that if ∧m is plotted against c1/2, we get a straight line with intercept A and slope equal to ‘A’. The value of constant ‘A’ at a given solvent and temperature depends on the type of electrolyte, i.e., on the charges of the cation and anion produced on dissociation of the electrolyte in solution. Thus, NaCl, CaCl2, and MgSO4 are known as 1-1, 2-1 and 2-2 electrolytes, respectively. The value of ‘A’ is the same for all electrolytes of the same type.

shaalaa.com
  Is there an error in this question or solution?
Chapter 2: Electrochemistry - Exercises [Page 59]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 2 Electrochemistry
Exercises | Q 2.7 (iii) | Page 59
Nootan Chemistry [English] Class 12 ISC
Chapter 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.7 iii. | Page 211

RELATED QUESTIONS

The conductivity of 0.20 M solution of KCl at 298 K is 0.025 S cm−1. Calculate its molar conductivity.


Define limiting molar conductivity.


Why conductivity of an electrolyte solution decreases with the decrease in concentration ?


Why does the conductivity of a solution decrease with dilution?


A steady current of 2 amperes was passed through two electrolytic cells X and Y connected in series containing electrolytes FeSO4and ZnSO4 until 2.8g of Fe deposited at the cathode of cell X. How long did the current flow? Calculate the mass of Zn deposited at the cathode of cell Y. 
(Molar mass: Fe=56g mol-1,Zn=65.3g mol-1,1F=96500C mol-1)


In the plot of molar conductivity (∧m) vs square root of concentration (c1/2), following curves are obtained for two electrolytes A and B:

Answer the following:
(i) Predict the nature of electrolytes A and B.
(ii) What happens on extrapolation of ∧m to concentration approaching zero for electrolytes A and B?


Molar conductivity of ionic solution depends on:

(i) temperature.

(ii) distance between electrodes.

(iii) concentration of electrolytes in solution.

(iv) surface area of electrodes.


Assertion: `"E"_("Ag"^+ //"Ag")` increases with increase in concentration of Ag+ ions.

Reason: `"E"_("Ag"^+ //"Ag")` has a positive value.


Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λm of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer. Graphically show the behavior of ‘A’ and ‘B’.


The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol−1. What is the dissociation constant of acetic acid? Choose the correct option.

\[\begin{array}{cc}
\end{array}\]\[\begin{bmatrix}
\ce{\Lambda^{\circ}_{H^+} = 350 S cm^2 mol^{-1}}\\
\ce{\Lambda^{\circ}_{CH_3COO^-} = 50 S cm^2 mol^{-1}}
\end{bmatrix}\]


The molar conductance of NaCl, HCl, and CH3COONa at infinite dilution are 126.45, 426.16, and 91.0 S cm2 mol−1 respectively. The molar conductance of CH3COOH at infinite dilution is. Choose the right option for your answer.


The molar conductivity of CH3COOH at infinite dilution is 390 Scm2/mol. Using the graph and given information, the molar conductivity of CH3COOK will be:


Molar conductivity of substance “A” is 5.9 × 103 S/m and “B” is 1 × 10–16 S/m. Which of the two is most likely to be copper metal and why?


Given below are two statements:

Statements I: The limiting molar conductivity of KCl (strong electrolyte) is higher compared to that of CH3COOH (weak electrolyte).

Statement II: Molar conductivity decreases with decrease in concentration of electrolyte.
In the light of the above statements, choose the most appropriate answer from the options given below:


The variation of molar conductivity with concentration of an electrolyte (X) m aqueous solution is shown in the given figure.

The electrolyte X is ______.


Assertion (A): Molar conductivity decreases with increase in concentration.

Reason (R): When concentration approaches zero, the molar conductivity is known as limiting molar conductivity.


The unit of molar conductivity is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×