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Karnataka Board PUCPUC Science 2nd PUC Class 12

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.

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Question

The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.

Numerical
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Solution

Given: κ = 2.48 × 10−2 Ω−1 cm−1

M = 0.20 mol L−1

m = `(kappa xx 1000)/("Molarity")`

= `(0.0248  S  cm^-1 xx 1000  cm^3  L^-1)/(0.20  mol  L^-1)`

= 124 S cm2 mol−1

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Chapter 2: Electrochemistry - Exercises [Page 59]

APPEARS IN

NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 2 Electrochemistry
Exercises | Q 2.8 | Page 59
Nootan Chemistry [English] Class 12 ISC
Chapter 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.8 | Page 211

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