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Question
The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 S cm−1. Calculate its molar conductivity.
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Solution
Given: κ = 2.48 × 10−2 Ω−1 cm−1
M = 0.20 mol L−1
∧m = `(kappa xx 1000)/("Molarity")`
= `(0.0248 S cm^-1 xx 1000 cm^3 L^-1)/(0.20 mol L^-1)`
= 124 S cm2 mol−1
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