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Question
The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10−3 S cm−1.
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Solution
Given: Conductivity, κ = 0.146 × 10−3 S cm−1
Resistance, R = 1500 Ω
∴ Cell constant = κ × R
= 0.146 × 10−3 × 1500
= 0.219 cm−1
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