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Karnataka Board PUCPUC Science 2nd PUC Class 12

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10^−3 S cm−1.

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Question

The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10−3 S cm−1.

Numerical
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Solution

Given: Conductivity (κ) = 0.146 × 10−3 S cm−1

Resistance (R) = 1500 Ω

∴ Cell constant = κ × R

= 0.146 × 10−3 × 1500

= 0.219 cm−1

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Chapter 2: Electrochemistry - Exercises [Page 59]

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NCERT Chemistry Part 1 and 2 [English] Class 12
Chapter 2 Electrochemistry
Exercises | Q 2.9 | Page 59
Nootan Chemistry [English] Class 12 ISC
Chapter 2 Electrochemistry
'NCERT TEXT-BOOK' Exercises | Q 3.9 | Page 211
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