Advertisements
Advertisements
Question
The resistance of a conductivity cell containing 0.001 M KCl solution at 298 K is 1500 Ω. What is the cell constant if the conductivity of 0.001 M KCl solution at 298 K is 0.146 × 10−3 S cm−1.
Advertisements
Solution
Given: Conductivity (κ) = 0.146 × 10−3 S cm−1
Resistance (R) = 1500 Ω
∴ Cell constant = κ × R
= 0.146 × 10−3 × 1500
= 0.219 cm−1
APPEARS IN
RELATED QUESTIONS
Define conductivity for the solution of an electrolyte.
Give reasons:
On the basis of E° values, O2 gas should be liberated at anode but it is Cl2 gas which is liberated in the electrolysis of aqueous NaCl.
Give reasons:
Conductivity of CH3COOH decreases on dilution.
When measuring conductivity with a conductivity cell, cell constant denoted by the symbol G* is given by (electrode area of cross-section equal to ‘A’ and separated by distance ‘l’)
The cell constant of a conductivity cell ______.
Conductivity of an electrolytic solution depends on:
(i) nature of electrolyte.
(ii) concentration of electrolyte.
(iii) power of AC source.
(iv) distance between the electrodes.
ConductivityK, is equal to:
(i) `1/R l/A`
(ii) `G^∗/R`
(iii) Λm
(iv) `l/A`
In an aqueous solution how does specific conductivity of electrolytes change with addition of water?
Assertion: Conductivity of all electrolytes decreases on dilution.
Reason: On dilution number of ions per unit volume decreases.
Assertion: For measuring resistance of an ionic solution an AC source is used.
Reason: Concentration of ionic solution will change if DC source is used.
Which of the following is not the characteristic of ionic solids?
The conductivity of 0.01 m NaCl solution is 0.00147 ohm–1cm–1. What happens to the conductivity if extra 100 ML is added to the above solution:-
The cell constant is the product of resistance and ______
The decreasing order of electrical conductivity of the following aqueous solutions is:
- 0.1 M Formic acid,
- 0.1 M Acetic acid,
- 0.1 M Benzoic acid.
