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Determine whether the following relation is reflexive, symmetric and transitive: Relation R in the set A = {1, 2, 3, 4, 5, 6} as R = {(x, y) : y is divisible by x}. - Mathematics

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Question

Determine whether the following relation is reflexive, symmetric and transitive:

Relation R in the set A = {1, 2, 3, 4, 5, 6} as R = {(x, y) : y is divisible by x}.

Sum
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Solution

A = {1, 2, 3, 4, 5, 6}

R = {(x, y) : y is divisible by x}

We know that any number (x) is divisible by itself.

⇒ (x, x) ∈ R

∴ R is reflexive.

Now, (2, 4) ∈ R  ....[As 4 is divisible by 2.]

But (4, 2) ∉ R  ....[As 2 is not divisible by 4.]

∴ R is not symmetric.

Let (x, y), (y, z) ∈ R. Then, y is divisible by x and z is divisible by y.

∴ z is divisible by x.

⇒ (x, z) ∈ R

∴ R is transitive.

Hence, R is reflexive and transitive but not symmetric.

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Chapter 1: Relations and Functions - Exercise 1.1 [Page 5]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 1 Relations and Functions
Exercise 1.1 | Q 1.3 | Page 5

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