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Determine P(E|F). Mother, father and son line up at random for a family picture E: son on one end, F: father in middle

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Determine P(E|F).

Mother, father and son line up at random for a family picture

E: son on one end, F: father in middle

Mother, Father and Son line up at random for a family picture. Let events E: Son on one end and F: Father in the middle. Find P(E/F).

Sum
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Solution

Let m, f and s denote respectively the mother, father and the son, then sample space S is S = {mfs, msf, fms, fsm, smf, sfm}.

E: son on one end

F: father in the middle

i.e., E = {mfs, fms, sfm, smf) and F = {sfm, mfs)

⇒ E ∩ F = {mfs, sfm)

`P (E) = 4/6 = 2/3`

`P (F) = 2/6 = 1/3`

`P (E cap F) = 2/6 = 1/3`

∴ `P (E|F) = (P (E cap F))/(P (F))`

`= (1/3)/(1/3)`

= 1

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Chapter 13: Probability - Exercise 13.1 [Page 539]

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NCERT Mathematics Part 1 and 2 [English] Class 12
Chapter 13 Probability
Exercise 13.1 | Q 9 | Page 539

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