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Question
Determine the nature of the roots of the following quadratic equation:
`3/5x^2-2/3x+1=0`
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Solution
The given quadric equation is `3/5x^2-2/3x+1=0`
⇒ 9x2 - 10x + 15 = 0
Here, a = 9, b = -10 and c = 15
As we know that D = b2 - 4ac
Putting the value of a = 9, b = -10 and c = 15
D = (-10)2 - 4(9)(15)
= 100 - 540
= -440
Since, D < 0
Therefore, root of the given equation are not real.
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