Question

Determine the nature of the roots of the following quadratic equation:

`3/5x^2-2/3x+1=0`

Answer 1

The given quadric equation is `3/5x^2-2/3x+1=0`

⇒ 9x² - 10x + 15 = 0

Here, a = 9, b = -10 and c = 15

As we know that D = b² - 4ac

Putting the value of a = 9, b = -10 and c = 15

D = (-10)² - 4(9)(15)

= 100 - 540

= -440

Since, D < 0

Therefore, root of the given equation are not real.