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Find the nature of the roots of the following quadratic equation. If the real roots exist, find them: 3x2 - 43x +4=0 - Mathematics

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Find the nature of the roots of the following quadratic equation. If the real roots exist, find them:

`3x^2 - 4sqrt3x + 4 = 0`

Determine the nature of the roots of the following quadratic equation:

`3x^2 - 4sqrt3x + 4 = 0`

Sum
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Solution

`3x^2 - 4sqrt3x + 4 = 0`

Comparing it with ax2 + bx + c = 0, we get

a = 3, b = `-4sqrt3`  and c = 4

Discriminant = b2 - 4ac

= `(-4sqrt3)^2 - 4(3)(4)`

= 48 - 48

= 0

As b2 - 4ac = 0,

Therefore, real roots exist for the given equation and they are equal to each other.

And the roots will be `(-b)/(2a) `

i.e, `(-(-4)sqrt3)/(2xx3) and (-(-4sqrt3))/(2xx3)`

= `(4sqrt3)/(2sqrt3 xx sqrt3) and (4sqrt3)/(2sqrt3 xxsqrt3)`

Therefore, the roots are `2/sqrt3 and 2/sqrt3.`

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Chapter 4: Quadratic Equations - Exercise 4.6 [Page 41]

APPEARS IN

RD Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.6 | Q 1.4 | Page 41
NCERT Mathematics [English] Class 10
Chapter 4 Quadratic Equations
EXERCISE 4.3 | Q 1. (ii) | Page 47

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