Advertisements
Advertisements
Question
Determine the nature of the roots of the following quadratic equation :
x2 +3x+1=0
Advertisements
Solution
x2 +3x+1=0
b2 - 4ac
= (3)2 - 4(1)(1)
= 9 - 4
= 5
Since discriminant is positive, hence the roots are real and irrational.
APPEARS IN
RELATED QUESTIONS
Without solving, examine the nature of roots of the equation x2 – 5x – 2 = 0
Find the value of the discriminant in the following quadratic equation :
x2 +2x+4=0
Solve the following quadratic equation using formula method only
16x2 - 24x = 1
If a = 1, b = 4, c = –5, then find the value of b2 – 4ac.
If p, q and r are rational numbers and p ≠ q ≠ r, then roots of the equation (p2 – q2)x2 – (q2 – r2)x + (r2 – p2) = 0 are:
Find the value of 'k' so that the quadratic equation 3x2 – 5x – 2k = 0 has real and equal roots.
If α and β be the roots of the equation x2 – 2x + 2 = 0, then the least value of n for which `(α/β)^n` = 1 is ______.
Find the value of k for which the roots of the quadratic equation 5x2 – 10x + k = 0 are real and equal.
Solve the following quadratic equation:
x2 + 4x – 8 = 0
Give your Solution correct to one decimal place.
(Use mathematical tables if necessary.)
The roots of quadratic equation x(x + 8) + 12 = 0 are ______.
