Advertisements
Advertisements
Question
Solve for x: 9x2 – 6px + (p2 – q2) = 0
Advertisements
Solution
a = 9, b = − 6p, c = p2 − q2
D = b2 − 4ac = (− 6p)2 − 4(9)(p2 − q2) = 36q2
x = `(- b +- sqrt(D))/(2q) = (6p +- 6q)/18 = (p + q)/3` or `(p - q)/3`
APPEARS IN
RELATED QUESTIONS
Solve the equation by using the formula method. 3y2 +7y + 4 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
x2 - kx + 9 = 0
In the following determine the set of values of k for which the given quadratic equation has real roots:
2x2 + kx + 2 = 0
If x = 2 and x = 3 are roots of the equation 3x² – 2kx + 2m = 0. Find the values of k and m.
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 5x + 7 = 0
Without solving the following quadratic equation, find the value of 'm' for which the given equation has real and equal roots.
x2 + 2(m – 1)x + (m + 5) = 0
If the roots of the given quadratic equation are real and equal, then find the value of ‘m’.
(m – 12)x2 + 2(m – 12)x + 2 = 0
State whether the following quadratic equation have two distinct real roots. Justify your answer.
x(1 – x) – 2 = 0
Solve the equation: 3x2 – 8x – 1 = 0 for x.
If the quadratic equation ax2 + bx + c = 0 has two real and equal roots, then 'c' is equal to ______.
