Advertisements
Advertisements
Question
Determine the nature of the roots of the following quadratic equation :
2x2 + 5x - 6 = 0
Advertisements
Solution
2x2 + 5x - 6 = 0
b2 - 4ac
= (5)2 - 4(2)(-6)
= 25 + 48
= 73
Since discriminant is positive, hence the roots are real and irrational.
APPEARS IN
RELATED QUESTIONS
Find the value of p for which the quadratic equation (2p + 1)x2 − (7p + 2)x + (7p − 3) = 0 has equal roots. Also find these roots.
For what value of m, are the roots of the equation (3m + 1)x2 + (11 + m) x + 9 = 0 equal?
Find the values of k for which the roots are real and equal in each of the following equation:
x2 - 2(5 + 2k)x + 3(7 + 10k) = 0
Find the values of k for which the roots are real and equal in each of the following equation:
(4 - k)x2 + (2k + 4)x + 8k + 1 = 0
Write the value of k for which the quadratic equation x2 – kx + 4 = 0 has equal roots.
Find the value of the discriminant in the following quadratic equation :
`4 sqrt 3 "x"^2 + 5"x" - 2 sqrt 3 = 0`
Without actually determining the roots comment upon the nature of the roots of each of the following equations:
x2 - 5x + 7 = 0
If one root of the equation x2+ px + 12 = 0 is 4, while the equation x2 + px + q = 0 has equal roots, the value of q is:
Find the roots of the quadratic equation by using the quadratic formula in the following:
–3x2 + 5x + 12 = 0
If b and c are odd integers, then the equation x2 + bx + c = 0 has ______.
