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Find the least positive value of k for which the equation x2 + kx + 4 = 0 has real roots. - Mathematics

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Question

Find the least positive value of k for which the equation x2 + kx + 4 = 0 has real roots. 

Sum
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Solution

The given quadric equation is x2 + kx + 4 = 0, and roots are real.

Then find the value of k.

Here,

a = 1, b = k and c = 4

As we know that D = b2 − 4ac

Putting the value of a = 1, b = k and c = 4

= k2 − 4 × (1) × (4)

= k2 − 16

The given equation will have real and equal roots, if D = 0

k2 − 16 = 0

Now factorizing of the above equation

k2 − 16 = 0

k2 = 16

`k=sqrt16`

k = ± 4

Now according to question, the value of k is positive.

Therefore, the value of k = 4

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Chapter 4: Quadratic Equations - Exercise 4.6 [Page 42]

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RD Sharma Mathematics [English] Class 10
Chapter 4 Quadratic Equations
Exercise 4.6 | Q 8 | Page 42

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