English
Karnataka Board PUCPUC Science Class 11

Consider a Long, Straight Wire of Cross-sectional Area a Carrying a Current I. Let There Be N Free Electrons per Unit Volume.

Advertisements
Advertisements

Question

Consider a long, straight wire of cross-sectional area A carrying a current i. Let there be n free electrons per unit volume. An observer places himself on a trolley moving in the direction opposite to the current with a speed  \[v = \frac{i}{\text{nAe}}\] and separation from the wire by a distance r. The magnetic field seen by the observer is very nearly  

Options

  • \[\frac{\mu_0 i}{2\pi r}\]
  • zero

  • \[\frac{\mu_0 i}{\pi r}\]
  • \[\frac{2 \mu_0 i}{\pi r}\]
MCQ
Advertisements

Solution

Magnetic field will be independent of the motion of the observer because the velocity with which the observer is moving is comparable to drift velocity of electron which is very small as compared to the speed of flow of current from one end of wire to other end. So it can be neglected  and hence, magnetic field due to the wire w.r.t the observer will be

B = \[\frac{\mu_o i}{2\pi r}\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 35: Magnetic Field due to a Current - MCQ [Page 249]

APPEARS IN

HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 35 Magnetic Field due to a Current
MCQ | Q 12 | Page 249

RELATED QUESTIONS

Find the condition under which the charged particles moving with different speeds in the presence of electric and magnetic field vectors can be used to select charged particles of a particular speed.


Show with the help of a diagram how the force between the two conductors would change when the currents in them flow in the opposite directions?


The motion of copper plate is damped when it is allowed to oscillate between the two poles of a magnet. What is the cause of this damping?


Two long straight parallel conductors carrying steady currents I1 and I2 are separated by a distance 'd'. Explain briefly, with the help of a suitable diagram, how the magnetic field due to one conductor acts on the other. Hence deduce the expression for the force acting between the two conductors. Mention the nature of this force.


Consider the situation shown in figure. The wires P1Q1 and P2Q2 are made to slide on the rails with the same speed 5 cm s−1. Suppose the 19 Ω resistor is disconnected. Find the current through P2Q2 if (a) both the wires move towards right and (b) if P1Q1 moves towards left but P2Q2 moves towards right.


A charged particle moves through a magnetic field perpendicular to its direction. Then ______.


If an electron is moving with velocity `vecnu` produces a magnetic field `vec"B"`, then ______.


Assertion(A): A proton and an electron, with same momenta, enter in a magnetic field in a direction at right angles to the lines of the force. The radius of the paths followed by them will be same.

Reason (R): Electron has less mass than the proton.

Select the most appropriate answer from the options given below:


A deuteron and an alpha particle having equal kinetic energy enter perpendicular into a magnetic field. Let `r_d` and `r_alpha` be their respective radii of the circular path. The value of `(r_d)/(r_alpha)` is equal to ______.


A wire carrying current i has the configuration shown in figure. For the magnetic field to be zero at the centre of the circle, θ must be:


A square coil ABCD with its plane vertical is released from rest in a horizontal uniform magnetic field `vec"B"` of length 2L. The acceleration of the coil is ______.


A conductor ABOCD moves along its bisector with a velocity 1 m/s through a perpendicular magnetic field of 1 wb/m2, as shown in figure. If all the four sides are 1 m length each, then the induced emf between A and Din approx is ______V.


An α particle is moving along a circle of radius R with a constant angular velocity ω. Point A lies in the same plane at a distance 2R from the centre. Point A records magnetic field produced by α particle, if the minimum time interval between two successive times at which A records zero magnetic field is 't' the angular speed ω, in terms of t is ______.


Why does a magnetic force change only the direction of a charged particle's motion and not its speed?


In uniform circular motion of a charged particle in a magnetic field, the magnetic force \[F = qvB\] acts as which of the following?


The frequency of revolution of a charged particle moving in a circular path in a magnetic field is:


For a charged particle moving at an angle θ to a magnetic field \[\vec B\] (0° < θ < 90°), the parallel component of velocity \[v_\parallel = v \cos\theta\]:


The pitch of the helix described by a charged particle in a magnetic field is given by:


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×