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A charged particle's velocity makes an angle θ with a magnetic field \[\vec B\], where 0° < θ < 90°. The perpendicular component of velocity \[v_\perp = v \sin\theta\] is responsible for:

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Question

A charged particle's velocity makes an angle θ with a magnetic field \[\vec B\], where 0° < θ < 90°. The perpendicular component of velocity \[v_\perp = v \sin\theta\] is responsible for:

Options

  • Increasing the kinetic energy of the particle

  • The acceleration of the particle along the direction of \[\vec B\]

  • The linear motion of the particle along \[\vec B\]

  • The circular motion of the particle

MCQ
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Solution

The velocity is resolved into two components: the perpendicular component \[v_\perp = v \sin\theta\], which is ⊥ to \[\vec B\] and causes circular motion, and the parallel component \[v_\parallel = v \cos\theta\], which is ∥ to \[\vec B\] and causes linear motion (unchanged).

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