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Classify the Following Functions as Injection, Surjection Or Bijection : F : R → R, Defined By F(X) = 1 + X2 - Mathematics

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Question

Classify the following function as injection, surjection or bijection :

f : R → R, defined by f(x) = 1 + x2

Sum
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Solution

f : R → R, defined by f(x) = 1 + x2

Injection test:
Let x and y be any two elements in the domain (R), such that f(x) = f(y).

f(x) = f(y)

1 + x2=1 + y2

x= y2

x = ± y

So, f is not an injection.
Surjection test:

Let y be any element in the co-domain (R), such that f(x) = y for some element x in R (domain).

f(x) = y

1 + x2= y

x2= y − 1

`x = ± sqrt-1 = ± i` is not in R.

So, f is not a surjection and f is not a bijection.

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Chapter 2: Functions - Exercise 2.1 [Page 31]

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RD Sharma Mathematics [English] Class 12
Chapter 2 Functions
Exercise 2.1 | Q 5.16 | Page 31

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