Advertisements
Advertisements
Question
Carry out the following divisions:
12a8b8 ÷ (−6a6b4)
Sum
Advertisements
Solution
12a8b8 = 2 × 2 × 3 × a8 × b8
−6a6b4 = −2 × 3 × a6 × b4
= 12a8b8 ÷ (−6a6b4)
= `(2 xx 2 xx 3 xx a^8 xx b^8)/(-2xx3xxa^6xxb^4)`
= `(2 xx a^2 xx b^4)/-1`
= −2a2b4
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Divide: −70a3 by 14a2
`(18"m"^4(_))/(2"m"^3"n"^3` = _____ mn5
`("l"^4"m"^5"n"^((_)))/(2"l""m"^((_))"n"^6) = ("l"^3"m"^3"n")/((_))`
`(42"a"^4"b"^5(_))/(6"a"^4"b"^2)` = `(_)"b"^((_))"c"^2`
Divide 45x3y2z4 by (−15xyz)
Divide (3xy)2 by 9xy
Simplify `(3"m"^2)/"m" + (2"m"^4)/("m"^3)`
Divide: (4m2n3 + 16m4n2 – mn) by 2mn
Statement A: 4x2 + 3x – 2 = `2(2x^2 + (3x)/2 - 1)`
Statement B: (2m – 5) – (5 – 2m) = (2m – 5) + (2m – 5)
What sum of money will earn ₹ 500 as simple interest in 1 year at 5% per annum?
