Advertisements
Advertisements
Question
Divide: 63a4b5c6 by −9a2b4c3
Sum
Advertisements
Solution
`(63"a"^4"b"^5"c"^6)/(-9"a"^2"b"^4"c"^3)=(63/(-9))("a"^4/"a"^2)("b"^5/"b"^4)("c"^6/"c"^3)`
= −7a4−2 . b5−4 . c6−3
= −7a2bc3
shaalaa.com
Is there an error in this question or solution?
APPEARS IN
RELATED QUESTIONS
Carry out the following divisions:
66pq2r3 ÷ 11qr2
Carry out the following divisions:
12a8b8 ÷ (−6a6b4)
Divide: 24x3y3 by −8y2
Divide: 15a4b by −5a3b
Do the following division.
-20x4 ÷ 10x2
Do the following division.
7x2y2z2 ÷ 14xyz
Divide (3xy)2 by 9xy
Divide: (4m2n3 + 16m4n2 – mn) by 2mn
Divide:
5xy2 – 18x2y3 + 6xy by 6xy
What sum of money will earn ₹ 500 as simple interest in 1 year at 5% per annum?
