42a2b5(_)6a4b2 = (__)b3c2

`(42"a"^4"b"^5(_))/(6"a"^4"b"^2)` = `(_)"b"^((_))"c"^2`

Fill in the Blanks

`(42"a"^4"b"^5("c"^2))/(6"a"^4"b"^2)` = (7)b³c²

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Chapter 3: Algebra - Exercise 3.2 [Page 85]

Chapter 3 Algebra
Exercise 3.2 | Q 1. (iii) | Page 85

Carry out the following divisions:

66pq²r³ ÷ 11qr²

Divide: −70a³ by 14a²

Divide: 24x³y³ by −8y²

`(18"m"^4(_))/(2"m"^3"n"^3` = _____ mn⁵

Divide 45x³y²z⁴ by (−15xyz)

Simplify `(3"m"^2)/"m" + (2"m"^4)/("m"^3)`

Statement A: 4x² + 3x – 2 = `2(2x^2 + (3x)/2 - 1)`

Statement B: (2m – 5) – (5 – 2m) = (2m – 5) + (2m – 5)

Find the simple interest on Rs. 5a²b² for 4ab years at 7b% per annum

The cost of a notebook is Rs. 10ab. If Babu has Rs. (5a²b + 20ab² + 40ab). Then how many notebooks can he buy?

What sum of money will earn ₹ 500 as simple interest in 1 year at 5% per annum?