42a2b5(_)6a4b2 = (__)b3c2

`(42"a"^4"b"^5(_))/(6"a"^4"b"^2)` = `(_)"b"^((_))"c"^2`

Fill in the Blanks

`(42"a"^4"b"^5("c"^2))/(6"a"^4"b"^2)` = (7)b³c²

shaalaa.com

Is there an error in this question or solution?

Chapter 3: Algebra - Exercise 3.2 [Page 85]

Chapter 3 Algebra
Exercise 3.2 | Q 1. (iii) | Page 85

Carry out the following divisions:

34x³y³z³ ÷ 51xy²z³

Carry out the following divisions:

12a⁸b⁸ ÷ (−6a⁶b⁴)

Divide: −70a³ by 14a²

Divide: 24x³y³ by −8y²

Divide: 63a⁴b⁵c⁶ by −9a²b⁴c³

`("l"^4"m"^5"n"^((_)))/(2"l""m"^((_))"n"^6) = ("l"^3"m"^3"n")/((_))`

Divide 45x³y²z⁴ by (−15xyz)

Simplify `(3"m"^2)/"m" + (2"m"^4)/("m"^3)`

Statement A: 4x² + 3x – 2 = `2(2x^2 + (3x)/2 - 1)`

Statement B: (2m – 5) – (5 – 2m) = (2m – 5) + (2m – 5)

Find the simple interest on Rs. 5a²b² for 4ab years at 7b% per annum