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Question
Carry out the following divisions:
34x3y3z3 ÷ 51xy2z3
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Solution
34 x3y3z3 = 2 × 17 × x × x × x × y × y × y × z × z × z
51 xy2z3 = 3 ×17 × x × y × y × z × z × z
= `(34x^3y^3z^3)/( 51xy^2z^3)`
= `(2 xx 17 xx x xx x xx x xx y xx y xx y xx z xx z xx z)/(3 xx 17 xx x xx y xx y xx z xx z xx z)`
= `2/3 xx x xx x xx y`
= `2/3 x^2y`
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