English
Karnataka Board PUCPUC Science 2nd PUC Class 12

Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is 8.0 × 10^3 N m2/C.

Advertisements
Advertisements

Question

Careful measurement of the electric field at the surface of a black box indicates that the net outward flux through the surface of the box is 8.0 × 103 N m2/C.

  1. What is the net charge inside the box?
  2. If the net outward flux through the surface of the box were zero, could you conclude that there were no charges inside the box? Why or Why not?
Numerical
Advertisements

Solution

(a) Φ = 8 × 103 N m2 C−1

`q/ε_0 = 8 xx 10^3` N m2 C1

∴ q = 8 × 103 ε0

= 8 × 103 × 8.85 × 1012

= 7.08 × 108 C

(b) As Φ = 0

`q_"net"/ε_0 = 0`

∴ `q_"net" = 0`

Even though a closed surface may have internal charges, the net charge it contains is zero.

shaalaa.com
  Is there an error in this question or solution?
Chapter 1: Electric Charge and Fields - EXERCISES [Page 43]

APPEARS IN

NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charge and Fields
EXERCISES | Q 1.16 | Page 43
NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charges and Fields
Exercise | Q 1.17 | Page 47

Video TutorialsVIEW ALL [2]

RELATED QUESTIONS

How does the electric flux due to a point charge enclosed by a spherical Gaussian surface get affected when its radius is increased?


Define electric flux.


Consider a uniform electric field E = 3 × 103 `hat i` N/C.

  1. What is the flux of this field through a square of 10 cm on a side whose plane is parallel to the yz plane?
  2. What is the flux through the same square if the normal to its plane makes a 60° angle with the x-axis?

Define Electric Flux.


Two charges of magnitudes +4Q and − Q are located at points (a, 0) and (− 3a, 0) respectively. What is the electric flux due to these charges through a sphere of radius ‘2a’ with its centre at the origin?


Figure shows three point charges +2q, −q and + 3q. Two charges + 2q and −q are enclosed within a surface ‘S’. What is the electric flux due to this configuration through the surface ‘S’?


A small plane area is rotated in an electric field. In which orientation of the area, is the flux of the electric field through the area maximum? In which orientation is it zero?


The following figure shows a closed surface that intersects a conducting sphere. If a positive charge is placed at point P, the flux of the electric field through the closed surface


The electric flux through a closed Gaussian surface depends upon ______.


The electric field in a region is given by `vec"E"` = 5 `hatk`N/C. Calculate the electric flux Through a square of side 10.0 cm in the following cases

  1. The square is along the XY plane
  2. The square is along XZ plane
  3. The normal to the square makes an angle of 45° with the Z axis.

A charge 'Q' µC is placed at the centre of a cube. The flux through one face and two opposite faces of the cube is respectively ______.


If the flux of the electric field through a closed surface is zero, then ______.

A charged particle q is placed at the centre O of cube of length L (A B C D E F G H). Another same charge q is placed at a distance L from O. Then the electric flux through ABCD is ______.


The SI unit of electric flux is ______.


Total electric flux coming out of a unit positive charge kept in air is ______.


The electric field in a region is given by `bar"E" = 4hat"i" + 10hat"j"` N/C. The flux of this field through a square of 10 cm on a side whose plane is parallel to the XZ plane.


A charge Qµc is placed at the centre of a cube the flux coming from any surface will be.


What will be the total flux through the faces of the cube (figure) with side of length a if a charge q is placed at

  1. A: a corner of the cube.
  2. B: mid-point of an edge of the cube.
  3. C: centre of a face of the cube.
  4. D: mid-point of B and C.

A hollow sphere of radius R has a point charge q at its centre. Electric flux emanating from the sphere is X. How will the electric flux change, if at all, when radius of the sphere is doubled?


A hollow sphere of radius R has a point charge q at its centre. Electric flux emanating from the sphere is X. How will the electric flux change, if at all, when charge q is replaced by an electric dipole?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×