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Question
Calculate the volume occupied by 8.8 g of CO2 at 31.1°C and 1 bar pressure. R = 0.083 bar L K–1 mol–1.
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Solution
It is known that,
`"pV" = "m"/"M" "RT"`
`=> "V" = ("mRT")/("Mp")`
Here
m = 8.8 g
R = 0.083 bar LK–1 mol–1
T = 31.1°C = 304.1 K
M = 44 g
p = 1 bar
Thus volume (V) = `(8.8 xx 0.083 xx 304.1)/(44xx1)`
= 5.04806 L
= 5.05 L
Hence, the volume occupied is 5.05 L.
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