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Calculate the ratio of two specific heats of polyatomic gas molecules.

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Question

Calculate the ratio of two specific heats of polyatomic gas molecules.  

Numerical
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Solution

  1. Gases that have molecules containing more than two atoms are termed polyatomic gases.
  2. Each molecule of the polyatomic gas has 3 translational degrees of freedom. Only linear molecules have 2 degrees of freedom for rotation. All other polyatomic molecules have 3 degrees of freedom for rotation.
  3. The number of degrees of freedom (f) for the vibrational motion of a polyatomic molecule depends on the geometric structure of the molecule, i.e., the arrangement of atoms in a molecule.
  4. Each such degree of freedom contributes average energy `2 xx 1/2`kBT from kinetic energy and potential energy terms.
  5. Therefore for 1 mole of a polyatomic gas, the internal energy is E = `3/2 N_Ak_BT + 3/2 N_Ak_BT + f × 2/2 N_Ak_BT`
    = (3 + f) NAkB
  6. Molar-specificific heats at constant volume and constant pressure are given as 
    Cv = (3 + f) R and Cp = (4 + f) R
    ∴ `gamma = C_p/C_v = (4 + f)/(3 + f)`
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Chapter 3: Kinetic Theory of gases and Radiation - Short Answer II

APPEARS IN

SCERT Maharashtra Physics [English] 12 Standard HSC
Chapter 3 Kinetic Theory of gases and Radiation
Short Answer II | Q 3

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