Question

A mixture of one mole of monoatomic gas and one mole of a diatomic gas (rigid) are kept at room temperature (27°C). The ratio of specific heat of gases at constant volume respectively is:

Options

• `7/5`

• `3/2`

• `3/5`

• `5/3`

Answer 1

`bb(3/5)`

Explanation:

For a monoatomic gas:

C_V = `3/2 R`

For a diatomic gas (rigid):

C_V = `5/2 R`

Since 1 mole of each gas is present, the ratio of their C_V is:

`C_(V, "mono")/(C_(V, "diatomic") = (3/2 R)/(5/2 R)`

= `3/5`

But the question asks “respectively” (monoatomic : diatomic), so the correct ratio is `3/5`.