Advertisements
Advertisements
Question
Calculate the minimum distance between point of application of force and axis of rotation of a rigid body, if a force 125 N produces a moment of force of 25.75 Nm.
Advertisements
Solution
Moment of force = Force × Perpendicular distance
25.75 Nm = 125 N × Perpendicular distance
Perpendicular distance =`25.75/125` = 0.206 m.
RELATED QUESTIONS
Where can a body execute free vibrations?
What do you mean by the clockwise and anti-clockwise moment of force?
Classify the following amongst contact and non-contact force.
force of tension in a string
Write an expression for the change in momentum of a body of mass m moving with velocity v if v << c.
State one way to reduce the moment of given force about a given axis of rotation.
Fig. shows a uniform meter scale weighing 100 N pivoted at its centre. Two weights of 500 N and 300 N are hung from the ruler as shown in fig.
(i) Calculate total clockwise and anticlockwise moments.
(ii) Calculate difference in clockwise moment and anticlockwise moment.
(iii) Calculate the distance from O where a 100 N weight should be suspended to balance the meter scale.
State the units of moment of force.
Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
A uniform metre rule rests horizontally on a knife-edge at the 60 cm mark when a mass of 10 gram is suspended from one end. At which end must this mass be suspended? What is the mass of the rule?
The diagram shows wheel O pivoted at point A. Three equal forces F1, F2 and F3 act at point B on the wheel.
- Which force will produce maximum moment about A?
- Give a reason for your answer in (a).
