Advertisements
Advertisements
प्रश्न
Calculate the minimum distance between point of application of force and axis of rotation of a rigid body, if a force 125 N produces a moment of force of 25.75 Nm.
Advertisements
उत्तर
Moment of force = Force × Perpendicular distance
25.75 Nm = 125 N × Perpendicular distance
Perpendicular distance =`25.75/125` = 0.206 m.
संबंधित प्रश्न
It is easier to open the door by pushing it at its free end.
Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force.
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
The spanner (or wrench) has a long handle.
A car of mass 600 kg is moving with a speed of 10 ms-1 while a scooter of mass 80 kg us moving with a speed of 50 ms-1. Compare their momentum.
What do you understand by the clockwise and anticlockwise moment of force? When is it taken positive?
The figure shows two forces each of magnitude 10 N acting at the point A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of two forces about the point.
- A,
- B and
- O situated exactly at the middle of the two forces.
A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 6 N. Draw a diagram to show the application of forces and calculate the moment of forces applied.
Explain the motion of a planet around the sun in a circular path.
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the difference of anticlockwise and clockwise moment
