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प्रश्न
Calculate the minimum distance between point of application of force and axis of rotation of a rigid body, if a force 125 N produces a moment of force of 25.75 Nm.
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उत्तर
Moment of force = Force × Perpendicular distance
25.75 Nm = 125 N × Perpendicular distance
Perpendicular distance =`25.75/125` = 0.206 m.
संबंधित प्रश्न
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Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
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Assertion & Reasoning
- Assertion: The sum of the clockwise moments is equal to the sum of the anticlockwise moments.
- Reason: The principle of conservation of momentum is valid if the external force on the system is zero.
