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प्रश्न
A potter turns his wheel by applying a force through the stick near the rim of wheel.
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उत्तर
A potter's wheel has a wheel pivoted at the centre. The potter turns the wheel by means of a stick at the rim of the wheel. He increases the perpendicular distance.
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संबंधित प्रश्न
A brass ball is hanging from a stiff cotton thread. Draw a neat labeled diagram showing the forces acting on the brass ball and cotton thread
Thrust is the ............ force acting on a surface.
Match the column
| Column A | Column B |
| (a) Camel | (1) broad and deep foundation |
| (b) Truck | (2) broad feet |
| (c) Knife | (3) six or eight tyres |
| (d) High building | (4) sharp cutting edge |
| (e) Thrust | (5) atm |
| (f) Moment of force | (6) N |
| (g) Atmospheric pressure | (7) N m |
State two effects of a force when applied on a body.
In Fig. a force F is applied in a direction passing through the pivoted point O of the body. Will the body rotate? Give reason to support your answer.
State one way to reduce the moment of given force about a given axis of rotation.
The diagram shows two forces F1 = 5 N and F2 = 3N acting at point A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m
Calculate:
- Moment of force F1 about O
- Moment of force F2 about O
- Total moment of the two forces about O.
Fig. shows a uniform meter scale weighing 100 N pivoted at its centre. Two weights of 500 N and 300 N are hung from the ruler as shown in fig.
(i) Calculate total clockwise and anticlockwise moments.
(ii) Calculate difference in clockwise moment and anticlockwise moment.
(iii) Calculate the distance from O where a 100 N weight should be suspended to balance the meter scale.
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the difference of anticlockwise and clockwise moment
What is meant by the term ‘moment of force’? If the moment of force is assigned a negative sign then will the turning tendency of the force be clockwise or anti-clockwise?
