Advertisements
Advertisements
प्रश्न
Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
Advertisements
उत्तर
Let the balance be at x cm from the 25 N force.
Anti-clockwise moment = 10 (12 − x)
Clockwise moment = 25 x
Applying the principle of moments,
⇒ 10 (12 − x) = 25 x
⇒ 120 − 10 x = 25 x
⇒ 35 x = 120
⇒ x = `120/35`
= 3.43 cm.
∴ The body balances at the 3.43 cm mark.
संबंधित प्रश्न
In a door, handle is provided ......... from the hinges.
Write the expression for the moment of force about a given axis of rotation.
On what factors does the effect of thrust on a surface depend?
A rocket is moving at a constant speed in space by burning its fuel and ejecting out the burnt gases through a nozzle. Answer the following
1) Is there any change in the momentum of the rocket? if yes, what causes the change in momentum?
2) Is there any force acting on the rocket? if yes, how much?
The moment of a force of 10 N about a fixed point O is 5 N m. Calculate the distance of the point O from the line of action of the force.
The figure shows two forces each of magnitude 10 N acting at the point A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of two forces about the point.
- A,
- B and
- O situated exactly at the middle of the two forces.
Explain the motion of a planet around the sun in a circular path.
Classify the following amongst contact and non-contact forces.
normal reaction force,
A meter scale is provided at 10 cm mark and is balanced by suspending 400 g from 0 cm mark (fig.). Calculate the mass of meter scale.
Under what condition will a set of gears produce a gain in torque.
