Advertisements
Advertisements
प्रश्न
Two unlike forces (parallel) of 10 N and 25 N act at a distance of 12 cm. from each other. Find the point about which the body balance.
Advertisements
उत्तर
Let the balance be at x cm from the 25 N force.
Anti-clockwise moment = 10 (12 − x)
Clockwise moment = 25 x
Applying the principle of moments,
⇒ 10 (12 − x) = 25 x
⇒ 120 − 10 x = 25 x
⇒ 35 x = 120
⇒ x = `120/35`
= 3.43 cm.
∴ The body balances at the 3.43 cm mark.
संबंधित प्रश्न
Where can a body execute free vibrations?
Moment of force = force × perpendicular distance of force – from the pivoted point.
State one factor on which the magnitude of a non-contact force depends. How does it depend on the factor stated by you?.
The diagram shows two forces F1 = 5 N and F2 = 3N acting at point A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m
Calculate:
- Moment of force F1 about O
- Moment of force F2 about O
- Total moment of the two forces about O.
State two factors affecting the turning effect of a force.
In a beam balance when the beam is balanced in a horizontal position, it is in ________ equilibrium.
State two factors on which moment of the force about a point depends.
State the units of moment of force.
Calculate the length of arm of couple, if a force of 13 N produces a moment of couple of 14.3 Nm.
A person standing in front of a cliff fires a gun and hears its echo after 3 s. If the speed of sound in air is 336 ms−1.
- Calculate the distance of the person from the cliff.
- After moving a certain distance from the cliff, he fires the gun again, and this time the echo is heard 1.5 s later than the first. Calculate the distance that the person moved.
