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Calculate Empirical Formula of a Compound.

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Question

A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]

Short/Brief Note
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Solution

Empirical formula of a compound:

Element Atomic
mass
Percentage Relative number of  Simplest mole ratio Whole number ratio 
Pb 207 90.66 90.66/207 = 0.44 0.44/0.44 = 1 1 x 3 = 3
O 16 9.34 9.34/16 = 0.58 0.58/0.44 = 1.32 1.32 x 3 = 3.96 = 4

Since the mole ratio for oxygen is fractional so we multiply the whole ratio by 3 to make i t a whole number.
So, the empirical formula of the compound is Pb3O4.

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Chapter 5: Mole Concept and Stoichiometry - Exercise 2 [Page 116]

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Frank Chemistry Part 2 [English] Class 10 ICSE
Chapter 5 Mole Concept and Stoichiometry
Exercise 2 | Q 6 | Page 116

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