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In a Compound of Magnesium (Mg = 24) and Nitrogen (N = 14), 18 G of Magnesium Combines with 7g of Nitrogen. Deduce the Simplest Formula by Answering the Follo

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Question

In a compound of magnesium (Mg = 24) and nitrogen (N = 14), 18 g of magnesium combines with 7g of nitrogen.

Deduce the simplest formula by answering the following questions:

  1. How many gram-atoms of magnesium are equal to 18g?
  2. How many gram-atoms of nitrogen are equal to 7g of nitrogen?
  3. Calculate the simple ratio of gram-atoms of magnesium to gram-atoms of nitrogen and hence the simplest formula of the compound formed.
Numerical
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Solution

(a) G atoms of magnesium = `18/24` = 0.75 or `3/4` g-atoms

(b) G atoms of nitrogen = `7/14` = 0.5 or `1/2` g-atoms

(c) As calculated above, 

Simplest ratio of `"g-atom of Mg"/"g-atom of N"`

= `(3/4)/(1/2)`

= `3/4 : 1/2`

∴ Mg : N = 3 : 2

∴ The simplest formula of the compound formed = Mg3N2

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Chapter 5: Mole concept and Stoichiometry - EXERCISE-5C [Page 95]

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S.P. Singh Concise Chemistry [English] Class 10 ICSE
Chapter 5 Mole concept and Stoichiometry
EXERCISE-5C | Q 15. | Page 95

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