मराठी

In a Compound of Magnesium (Mg = 24) and Nitrogen (N = 14), 18 G of Magnesium Combines with 7g of Nitrogen. Deduce the Simplest Formula by Answering the Follo

Advertisements
Advertisements

प्रश्न

In a compound of magnesium (Mg = 24) and nitrogen (N = 14), 18 g of magnesium combines with 7g of nitrogen.

Deduce the simplest formula by answering the following questions:

  1. How many gram-atoms of magnesium are equal to 18g?
  2. How many gram-atoms of nitrogen are equal to 7g of nitrogen?
  3. Calculate the simple ratio of gram-atoms of magnesium to gram-atoms of nitrogen and hence the simplest formula of the compound formed.
संख्यात्मक
Advertisements

उत्तर

(a) G atoms of magnesium = `18/24` = 0.75 or `3/4` g-atoms

(b) G atoms of nitrogen = `7/14` = 0.5 or `1/2` g-atoms

(c) As calculated above, 

Simplest ratio of `"g-atom of Mg"/"g-atom of N"`

= `(3/4)/(1/2)`

= `3/4 : 1/2`

∴ Mg : N = 3 : 2

∴ The simplest formula of the compound formed = Mg3N2

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 5: Mole concept and Stoichiometry - EXERCISE-5C [पृष्ठ ९०]

APPEARS IN

एस.पी. सिंह Concise Chemistry [English] Class 10 ICSE
पाठ 5 Mole concept and Stoichiometry
EXERCISE-5C | Q 17. | पृष्ठ ९०

संबंधित प्रश्‍न

A compound of X and Y has the empirical formula XY2. Its vapor density is equal to its empirical formula weight. Determine its molecular formula.


Identify the term or substance based on the descriptions given below:

The property by virtue of which the compound has the same molecular formula but different structural formulae.


Consider the following reaction and based on the reaction answer the questions that follow:

Calculate:

1) the quantity in moles of (NH4)2Cr2O7 if 63gm of(NH4)2Cr2O7 is heated.

2) the quantity in moles of nitrogen formed.

3) the volume in liters or dm3 of N2 evolved at S.T.P.

4) the mass in grams of Cr2O3 formed at the same time

(Atomic masses: H=1, Cr= 52, N=14]


Ethane burns in oxygen to form CO2 and H2O according to the equation:

`2C_2H_6+7O_2 -> 4CO_2 + 6H_2O`

If 1250 cc of oxygen is burnt with 300 cc of ethane.

Calculate:

1) the volume of `CO_2` formed

2) the volume of unused `O_2`


Give example of compound whose:
Empirical formula is the same as the molecular formula.


The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.


The compound A has the following percentage composition by mass: C =26.7%, O = 71.1%, H = 2.2%.
Determine the empirical formula of A.(Answer to one decimal place)  (H=1,C=12,O=16)


Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.


A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.


Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×