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Question
Ethane burns in oxygen to form CO2 and H2O according to the equation:
`2C_2H_6+7O_2 -> 4CO_2 + 6H_2O`
If 1250 cc of oxygen is burnt with 300 cc of ethane.
Calculate:
1) the volume of `CO_2` formed
2) the volume of unused `O_2`
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Solution
So, ethane is limiting reagent.
1) 2 x 22400 cc ethane give -> 4 x 22400 cc `CO_2`
∴ 300 cc ethane given → `(4xx22400xx300)/(2xx22400) "cc" Co_2`
= 600 cc CO2
2) For 300 cc Ethane 1050 cc of O2 will be required.
So unused O2 is (1250-1050) = 200 cc
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