Advertisements
Advertisements
Question
Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)
Advertisements
Solution
| Element | Atomic mass | Percentage | Relative number of moles | Simplest mole ratio | Whole number ratio |
| Na | 23 | 37.6 | 37.6/23 = 1.63 | 1.63/0.83 = 1.9 | 2 |
| Si | 28 | 23.1 | 23.1/28 = 0.83 | 0.83/0.83 = 1 | 1 |
| O | 16 | 39.3 | 39.3/16 = 2.45 | 2.45/0.83 = 2.9 | 3 |
So the empirical formula of the compound is Na2SiO3.
APPEARS IN
RELATED QUESTIONS
If the empirical formula of a compound is CH and it has a vapor density of 13, find the molecular formula of the compound.
Give the appropriate term defined by the statements given below :
The formula that represents the simplest ratio of the various elements present in one molecule of the compound.
Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]
Give the empirical formula of: C6H12O6
Give example of compound whose:
Empirical formula is the same as the molecular formula.
Give example of compound whose:
Empirical formula is different from the molecular formula.
A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]
A compound 'X' consists of 4.8% of C and 95.2% of Br by mass.
Determine the empirical formula of this compound.
[C = 12, Br = 80]
Explain the term empirical formula.
Pratik heated 11.2 grams of element ‘M’ (atomic weight 56) with 4.8 grams of element 'N' (atomic weight 16) to form a compound. Find the empirical formula of the compound obtained by Pratik.
