Question

(NH₄)₂Cr₂O₇ → N₂ + Cr₂O₃ +4H₂O.
What volume of nitrogen at STP, will be evolved when 63g of ammonium dichromate is decomposed?
(H= 1, N = 14, 0 = 16, Cr = 52)

Answer 1

Molecular mass of ammonium dichromate = 252
Now, 252g of ammonium dichromate evolves= 22.4 L of nitrogen at STP
63g of ammonium dichromate will evolve= 22.4 x 63 /252 = 5.6L
So, 63g of ammonium dichromate will evolve 5.6L of oxygen.