हिंदी

Calculate the Empirical Formula of the Compound Having 37.6% Sodium, 23.1% Silicon and 39.3% Oxygen.(Answer Correct to Two Decimal Places) (O = 16, Na = 23, Si = 28)

Advertisements
Advertisements

प्रश्न

Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)

टिप्पणी लिखिए
Advertisements

उत्तर

Element Atomic mass Percentage Relative number of moles Simplest  mole ratio Whole number  ratio 
Na 23 37.6 37.6/23 = 1.63 1.63/0.83 = 1.9 2
Si 28 23.1 23.1/28 = 0.83 0.83/0.83 = 1 1
O 16 39.3 39.3/16 = 2.45 2.45/0.83 = 2.9 3

So the empirical formula of the compound is Na2SiO3.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole Concept and Stoichiometry - Questions from ICSE Examinations [पृष्ठ ११३]

APPEARS IN

फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 5 Mole Concept and Stoichiometry
Questions from ICSE Examinations | Q 1997. 3. (a) | पृष्ठ ११३

संबंधित प्रश्न

A compound made up of two elements X and Y has an empirical formula X2Y. If the atomic weight of X is 10 and that of Y is 5 and the compound ha a vapor density 25, find its molecular formula.


 Find the empirical formula and the molecular formula of an organic compound from the data given below : 
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]


Give the empirical formula of C6H6.


A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.


The compound A has the following percentage composition by mass: C =26.7%, O = 71.1%, H = 2.2%.
Determine the empirical formula of A.(Answer to one decimal place)  (H=1,C=12,O=16)


The percentage composition of sodium phosphate, as determined by analysis is : 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound.
[H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]


Explain the term empirical formula.


0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.


Give the empirical formula of C6H18O3.


  1. A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correctly to 1 decimal place. (H = 1; C = 12; Cl = 35.5)
  2. The relative molecular mass of this compound is 168, so what is its molecular formula?
  3. By what type of reaction could this compound be obtained from ethyne?

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×