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प्रश्न
Give example of compound whose:
Empirical formula is different from the molecular formula.
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उत्तर
C6H12O6.
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संबंधित प्रश्न
A compound of X and Y has the empirical formula XY2. Its vapor density is equal to its empirical formula weight. Determine its molecular formula.
If the empirical formula of a compound is CH and it has a vapor density of 13, find the molecular formula of the compound.
Give the appropriate term defined by the statements given below :
The formula that represents the simplest ratio of the various elements present in one molecule of the compound.
Give the empirical formula of CH3COOH
Give example of compound whose:
Empirical formula is the same as the molecular formula.
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.
In a compound of magnesium (Mg = 24) and nitrogen (N = 14), 18 g of magnesium combines with 7g of nitrogen.
Deduce the simplest formula by answering the following questions:
- How many gram-atoms of magnesium are equal to 18g?
- How many gram-atoms of nitrogen are equal to 7g of nitrogen?
- Calculate the simple ratio of gram-atoms of magnesium to gram-atoms of nitrogen and hence the simplest formula of the compound formed.
A compound is formed by 24 g of X and 64 g of oxygen. If the atomic mass of X = 12 and O = 16, calculate the simplest formula of the compound.
