Advertisements
Advertisements
प्रश्न
Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]
Advertisements
उत्तर
| Element | % | |
| C | 75.92 | `75.92/12 = 6.32/1.26 = 5` |
| H | 6.32 | `6.32/1 = 6.32/1.26 = 5` |
| N | 17.76 | `17.76/14 = 1.26/1.26 = 1` |
Empirical formula ; - C5H5N
Molecular weight = 2 × Vapour Density
= 2 × 39.5
= 79
Empirical formula weight = C × 5 + H × 5 + N × 1
= 12 × 5 + 1 × 5 + 14 × 1
= 60 + 5 + 14
= 79
`n = "Molecular weight"/("Empirical" "formula" "weight" )`
∴ Molecular formula = Empirical formula = C5H5N
APPEARS IN
संबंधित प्रश्न
Identify the term or substance based on the descriptions given below:
The property by virtue of which the compound has the same molecular formula but different structural formulae.
Ethane burns in oxygen to form CO2 and H2O according to the equation:
`2C_2H_6+7O_2 -> 4CO_2 + 6H_2O`
If 1250 cc of oxygen is burnt with 300 cc of ethane.
Calculate:
1) the volume of `CO_2` formed
2) the volume of unused `O_2`
Give the empirical formula of C6H6.
Give the empirical formula of C2H2
Give example of compound whose:
Empirical formula is the same as the molecular formula.
A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Give the empirical formula of C6H18O3
The Empirical formula of an organic compound is CHCl2.
If its relative molecular mass is 168, what is its molecular formula?
[At. Wt. C = 12, H = 1, Cl = 35.5]
A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. By what type of reaction could this compound be obtained from ethylene?
