Advertisements
Advertisements
प्रश्न
A compound of X and Y has the empirical formula XY2. Its vapor density is equal to its empirical formula weight. Determine its molecular formula.
Advertisements
उत्तर
Given:
Empirical formula = XY2
Vapor density = Empirical formula weight
Molecular formula =?
Molecular weight = n(Empirical formula weight)
= 2 x V.D.
n(Empirical formula weight) = 2 x V.D.
Since Vapour density Empirical formula weight
n = 2
Molecular formula = 2(Empirical formula)
= 2(XY2)
Molecular formula = X2Y4
APPEARS IN
संबंधित प्रश्न
If the empirical formula of a compound is CH and it has a vapor density of 13, find the molecular formula of the compound.
Consider the following reaction and based on the reaction answer the questions that follow:

Calculate:
1) the quantity in moles of (NH4)2Cr2O7 if 63gm of(NH4)2Cr2O7 is heated.
2) the quantity in moles of nitrogen formed.
3) the volume in liters or dm3 of N2 evolved at S.T.P.
4) the mass in grams of Cr2O3 formed at the same time
(Atomic masses: H=1, Cr= 52, N=14]
Give the empirical formula of: C6H12O6
Give example of compound whose:
Empirical formula is the same as the molecular formula.
Give example of compound whose:
Empirical formula is different from the molecular formula.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.
0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.
Give the empirical formula of C6H18O3
The Empirical formula of an organic compound is CHCl2.
If its relative molecular mass is 168, what is its molecular formula?
[At. Wt. C = 12, H = 1, Cl = 35.5]
