Advertisements
Advertisements
प्रश्न
A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapor density is 29, find its molecular formula. [C = 12, H = 11]
Advertisements
उत्तर
| Element | Percentage | Molecules | Simple ratio | Ration | Simple whole ratio |
| Carbon | 82.76 | `82.76/12` = 6.9 | `6.89/6.89` = 1 | `6.9/6.9` = 1 | 2 |
| Hydrogen | 17.24 | `17.24/1` = 17.24 | `17.24/6.89` = 2.5 | `17.24/6.9` = 2.5 | 5 |
Empirical formula = C2H5
Empirical formula mass = (12 × 2) + (1 × 5)
= 24 + 5
= 29
Vapour density = 29 ...(Given)
Molecular weight = 2 × Vapour density
Molecular weight = 2 × 29
= 58 gm
Molecular formula mass = n × Empirical formula mass
⇒ n = `"Molecular formula mass"/"Empirical formula mass"`
= `58/29`
= 2
Molecular formula = n × Empirical formula
= 2 × C2H5
= C4H10
APPEARS IN
संबंधित प्रश्न
A compound made up of two elements X and Y has an empirical formula X2Y. If the atomic weight of X is 10 and that of Y is 5 and the compound ha a vapor density 25, find its molecular formula.
Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]
Give the empirical formula of C2H2
Give example of compound whose:
Empirical formula is the same as the molecular formula.
The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.
The compound A has the following percentage composition by mass: C =26.7%, O = 71.1%, H = 2.2%.
Determine the empirical formula of A.(Answer to one decimal place) (H=1,C=12,O=16)
The percentage composition of sodium phosphate, as determined by analysis is : 42.1% Na, 18.9% P, 39% of O. Find the empirical formula of the compound.
[H =1, N =14, Na = 23, P = 31, Cl = 35.5, Pt = 195]
A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.
0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.
Calculate:
Write the empirical formula of C8H18.
