Advertisements
Advertisements
प्रश्न
A compound made up of two elements X and Y has an empirical formula X2Y. If the atomic weight of X is 10 and that of Y is 5 and the compound ha a vapor density 25, find its molecular formula.
Advertisements
उत्तर
Empirical formula = X2Y
Atomic Weight (X) = 10
Atomic Weight (Y) = 5
Empirical Formula Weght = 2 × 10 + 5 = 25
So, n = `"Molecular weight"/"Empirical formula weight" = (2xx"V.D")/"Empirical formula weight"`
`n = (2 xx 25)/25 = 2`
So Molecular Formula = (X2Y) × 2 = X4Y2
APPEARS IN
संबंधित प्रश्न
A gaseous hydrocarbon contains 82.76% of carbon. Given that its vapor density is 29, find its molecular formula. [C = 12, H = 11]
Consider the following reaction and based on the reaction answer the questions that follow:

Calculate:
1) the quantity in moles of (NH4)2Cr2O7 if 63gm of(NH4)2Cr2O7 is heated.
2) the quantity in moles of nitrogen formed.
3) the volume in liters or dm3 of N2 evolved at S.T.P.
4) the mass in grams of Cr2O3 formed at the same time
(Atomic masses: H=1, Cr= 52, N=14]
Give the empirical formula of C6H6.
Give example of compound whose:
Empirical formula is different from the molecular formula.
A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
The compound A has the following percentage composition by mass: C =26.7%, O = 71.1%, H = 2.2%.
Determine the empirical formula of A.(Answer to one decimal place) (H=1,C=12,O=16)
Explain the term empirical formula.
Give the empirical formula of C6H18O3.
Calculate:
Write the empirical formula of C8H18.
