Advertisements
Advertisements
प्रश्न
Silicon (Si = 28) forms a compound with chlorine (Cl = 35.5) in which 5.6 g of silicon combines with 21.3 g of chlorine. Calculate the empirical formula of the compound.
Advertisements
उत्तर
Mass of silicon in the given compound = 5.6 g
Mass of the chlorine in the given compound = 21.3 g
The total mass of the compound = (5.6 g + 21.3)g = 26.9 g
% age of silicon in the compound = `56/26.9 × 100` = 20.82%
% age of chlorine in the compound = `21.2/26.9 × 100` = 79.18%
| Element | % age | At. wt. | Atomic ratio | Simplest ratio |
| Si | 20.82 | 28 | `20.82/28` = 0.74 | `0.74/0.74` = 1 |
| Cl | 79.18 | 35.5 | `79.18/35.5` = 2.23 | `2.23/0.74` = 3 |
∴ The empirical formula of the given compound = SiCl3
APPEARS IN
संबंधित प्रश्न
If the empirical formula of a compound is CH and it has a vapor density of 13, find the molecular formula of the compound.
A compound made up of two elements X and Y has an empirical formula X2Y. If the atomic weight of X is 10 and that of Y is 5 and the compound ha a vapor density 25, find its molecular formula.
Give the empirical formula of C6H6.
Give the empirical formula of CH3COOH
A compound of lead has following percentage composition, Pb = 90.66%, O = 9.34%. Calculate empirical formula of a compound. [Pb = 207, O = 16]
Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)
The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.
Determine the empirical formula of the compound whose composition by mass is 42% nitrogen, 48% oxygen and 9% hydrogen.[N=14,O=16,H=1]
A compound of X and Y has the empirical formula XY2. Its vapour density is equal to its empirical formula weight. Determine its molecular formula.
Give the empirical formula of C6H18O3
