हिंदी

Silicon (Si = 28) forms a compound with chlorine (Cl = 35.5) in which 5.6 g of silicon combines with 21.3 g of chlorine. Calculate the empirical formula of the compound.

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प्रश्न

Silicon (Si = 28) forms a compound with chlorine (Cl = 35.5) in which 5.6 g of silicon combines with 21.3 g of chlorine. Calculate the empirical formula of the compound.

संख्यात्मक
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उत्तर

Mass of silicon in the given compound = 5.6 g

Mass of the chlorine in the given compound = 21.3 g

The total mass of the compound = (5.6 g + 21.3)g = 26.9 g

% age of silicon in the compound = `56/26.9 × 100` = 20.82%

% age of chlorine in the compound = `21.2/26.9 × 100` = 79.18%

Element % age  At. wt. Atomic ratio Simplest ratio
Si 20.82 28 `20.82/28` = 0.74 `0.74/0.74` = 1
Cl 79.18 35.5 `79.18/35.5` = 2.23 `2.23/0.74` = 3

∴ The empirical formula of the given compound = SiCl3

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अध्याय 5: Mole concept and Stoichiometry - MISCELLANEOUS EXERCISE [पृष्ठ ९६]

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एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
MISCELLANEOUS EXERCISE | Q 15. | पृष्ठ ९६

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