Advertisements
Advertisements
प्रश्न
Silicon (Si = 28) forms a compound with chlorine (Cl = 35.5) in which 5.6 g of silicon combines with 21.3 g of chlorine. Calculate the empirical formula of the compound.
Advertisements
उत्तर
Mass of silicon in the given compound = 5.6 g
Mass of the chlorine in the given compound = 21.3 g
The total mass of the compound = (5.6 g + 21.3)g = 26.9 g
% age of silicon in the compound = `56/26.9 × 100` = 20.82%
% age of chlorine in the compound = `21.2/26.9 × 100` = 79.18%
| Element | % age | At. wt. | Atomic ratio | Simplest ratio |
| Si | 20.82 | 28 | `20.82/28` = 0.74 | `0.74/0.74` = 1 |
| Cl | 79.18 | 35.5 | `79.18/35.5` = 2.23 | `2.23/0.74` = 3 |
∴ The empirical formula of the given compound = SiCl3
संबंधित प्रश्न
Explain the terms empirical formula and molecular formula.
Give the empirical formula of: C6H12O6
Give the empirical formula of C2H2
A compound contains 87.5% by mass of nitrogen and 12.5% by mass of hydrogen. Determine the empirical formula of this compound.
Determine the empirical formula of a compound containing 47.9‰ K, 5.5‰ beryllium and 46.6‰ fluorine by mass.
Find the percentage of mass water in Epsom salt MgSO4.7H2O.
Explain the term empirical formula.
Give the empirical formula of C6H18O3
A compound is formed by 24 g of X and 64 g of oxygen. If the atomic mass of X = 12 and O = 16, calculate the simplest formula of the compound.
Calculate:
Write the empirical formula of C8H18.
