Advertisements
Advertisements
प्रश्न
Give example of compound whose:
Empirical formula is different from the molecular formula.
Advertisements
उत्तर
C6H12O6.
APPEARS IN
संबंधित प्रश्न
Ethane burns in oxygen to form CO2 and H2O according to the equation:
\[\ce{2C2H6 + 7O2 -> 4CO2 + 6H2O}\]
If 1250 cc of oxygen is burnt with 300 cc of ethane, calculate:
- the volume of CO2 formed.
- the volume of unused O2.
Find the empirical formula and the molecular formula of an organic compound from the data given below :
C = 75.92%, H = 6.32% and N = 17.76%
The vapour density of the compound is 39.5.
[C = 12, H = 1, N = 14]
Give the empirical formula of: C6H12O6
Give example of compound whose:
Empirical formula is the same as the molecular formula.
Calculate the empirical formula of the compound having 37.6% sodium, 23.1% silicon and 39.3% oxygen.(Answer correct to two decimal places) (O = 16, Na = 23, Si = 28)
The empirical formula of a compound is C2H5. Its vapour density is 29. Determine the relative molecular mass of the compound and hence its molecular formula.
0.2 g atom of silicon combine with 21.3 g of chlorine. Find the empirical formula of the compound formed.
- A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. Determine the empirical formula of this compound. Work correctly to 1 decimal place. (H = 1; C = 12; Cl = 35.5)
- The relative molecular mass of this compound is 168, so what is its molecular formula?
- By what type of reaction could this compound be obtained from ethyne?
The Empirical formula of an organic compound is CHCl2.
If its relative molecular mass is 168, what is its molecular formula?
[At. Wt. C = 12, H = 1, Cl = 35.5]
A compound has the following percentage composition by mass: carbon 14.4%, hydrogen 1.2% and chlorine 84.5%. By what type of reaction could this compound be obtained from ethylene?
