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Question
Assume that the mass of a nucleus is approximately given by M = Amp where A is the mass number. Estimate the density of matter in kgm−3 inside a nucleus. What is the specific gravity of nuclear matter?
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Solution
Given :-
Mass of the nucleus, M = Amp
Volume of the nucleus, V = `4/3piR_0^3A`
Density of the matter, d = `M/V = (Am_p)/(4/3piR_0^3A)`
`= (3m_p)/(4 xx piR_0^3)`
`= (3 xx 1.007276)/(4 xx 3.14(1.1)^3)`
`= 3 xx 10^17 "kg/m"^3`
Specific gravity of the nuclear matter = `("Density of matter")/("Density of water")`
`therefore` Specific gravity = `(3 xx 10^17)/10^3 = 3 xx 10^14 "kg/m"^3`
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