Advertisements
Advertisements
Question
Area of a right-angled triangle is 30 cm2. If its smallest side is 5 cm, then its hypotenuse is ______.
Options
14 cm
13 cm
12 cm
11 cm
Advertisements
Solution
Area of a right-angled triangle is 30 cm2. If its smallest side is 5 cm, then its hypotenuse is 13 cm.
Explanation:
Given, area of a right-angled triangle = 30 cm2
And smallest side i.e. base = 5 cm
We know that,
Area of right angled triangle = `1/2` × Base × Height
∴ 30 = `1/2` × 5 × Height
⇒ Height = `(30 xx 2)/5`
⇒ Height = 12 cm
Now, according to Pythagoras theorem,
(Hypotenuse)2 = (Perpendicular)2 + (Base)2
⇒ (Hypotenuse)2 = (12)2 + (5)2 ...[∵ Height = Perpendicular]
⇒ (Hypotenuse)2 = 144 + 25
⇒ (Hypotenuse)2 = 169
⇒ Hypotenuse = `sqrt(169)`
⇒ Hypotenuse = 13 cm
APPEARS IN
RELATED QUESTIONS
The area of a triangle is 5 sq units. Two of its vertices are (2, 1) and (3, –2). If the third vertex is (`7/2`, y). Find the value of y
Find the angle subtended at the origin by the line segment whose end points are (0, 100) and (10, 0).
Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200 cm ?
Find the area of ΔABC whose vertices are:
A( 3,8) , B(-4,2) and C( 5, -1)
Show that ∆ ABC with vertices A (–2, 0), B (0, 2) and C (2, 0) is similar to ∆ DEF with vertices D (–4, 0), F (4, 0) and E (0, 4) ?
Using integration, find the area of triangle ABC, whose vertices are A(2, 5), B(4, 7) and C(6, 2).
Find the area of the triangle whose vertices are (-2, 6), (3, -6), and (1, 5).
Area of a triangle = `1/2` base × ______.
In the following figure, ratio of the area of triangle ABC to the area of triangle ACD is the same as the ratio of base BC of triangle ABC to the base CD of triangle ACD.

Area of a triangle PQR right-angled at Q is 60 cm2 (see figure). If the smallest side is 8 cm long, find the length of the other two sides.

