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Question
Answer the following question:
Two farmers Shantaram and Kantaram cultivate three crops rice,wheat and groundnut. The sale (In Rupees) of these crops by both the farmers for the month of April and may 2008 is given below,
| April sale (In Rs.) | |||
| Rice | Wheat | Groundnut | |
| Shantaram | 15000 | 13000 | 12000 |
| Kantaram | 18000 | 15000 | 8000 |
| May sale (In Rs.) | |||
| Rice | Wheat | Groundnut | |
| Shantaram | 18000 | 15000 | 12000 |
| Kantaram | 21000 | 16500 | 16000 |
Find The total sale in rupees for two months of each farmer for each crop
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Solution
The given information can be written in the matrix form as :
April sale
A = `[("Rice", "wheat", "Groundnut"),(15000, 13000, 12000),(18000, 15000, 8000)] ":Shantaram"/":Kantaram"`
May sale
B = `[("Rice", "wheat", "Groundnut"),(18000, 13000, 12000),(21000, 16500, 16000)] ":Shantaram"/":Kantaram"`
The total sales in ₹ for two months of each former for each crop is obtained by addition of the matrices A and B.
i.e., A + B
= `[(15000, 13000, 12000),(18000, 15000, 8000)] + [(18000, 15000, 12000),(21000, 16500, 16000)]`
= `[(15000 + 18000, 13000 + 15000, 12000 + 12000),(18000 + 21000, 15000 + 16500, 8000 + 16000)]`
= `[(33000, 28000, 24000),(39000, 31500, 24000)]`
∴ total sales in ₹ for two months of each farmer is given by:
`[("Rice", "wheat", "Groundnut"),(33000, 28000, 24000),(39000, 31500, 24000)] ":Shantaram"/":Kantaram"`
Hence, the total sales (in ₹) of April and May for Shantaram is ₹ 33000 (rice), ₹ 28000 (wheat) and ₹ 24000 (groundnut) and Kantaram is ₹ 39000 (rice), ₹ 31500 (wheat) and ₹ 24000 (groundnut).
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| April sale (In Rs.) | |||
| Rice | Wheat | Groundnut | |
| Shantaram | 15000 | 13000 | 12000 |
| Kantaram | 18000 | 15000 | 8000 |
| May sale (In Rs.) | |||
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| Kantaram | 21000 | 16500 | 16000 |
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