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Answer the following question: If A = [0110] and B = [0-110] show that (A + B)(A – B) ≠ A2 – B2

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Question

Answer the following question:

If A = `[(0, 1),(1, 0)]` and B = `[(0, -1),(1, 0)]` show that (A + B)(A – B) ≠ A2 – B

Sum
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Solution

A + B = `[(0, 1),(1, 0)] + [(0, -1),(1, 0)]` 

= `[(0, 0),(2, 0)]`

A – B = `[(0, 1),(1, 0)] - [(0, -1),(1, 0)]`

= `[(0, 2),(0, 0)]`

∴ (A + B)(A – B) = `[(0, 0),(2, 0)] [(0, 2),(0, 0)]`

= `[(0 + 0, 0 + 0),(0 + 0, 4 + 0)]`

= `[(0, 0),(0, 4)]`  ...(1)

Also, A2 = A·A = `[(0, 1),(1, 0)] [(0, 1),(1, 0)]`

= `[(0 + 1, 0 + 0),(0 + 0, 1 + 0)]`

= `[(1, 0),(0, 1)]`

B2 = B·B = `[(0, -1),(1, 0)] [(0, -1),(1, 0)]`

= `[(0 - 1, 0 - 0),(0 + 0, -1 + 0)]`

= `[(-1, 0),(0, -1)]`

∴ A2 – B = `[(1, 0),(0, 1)] - [(-1, 0),(0, -1)]`

= `[(2, 0),(0, 2)]`

From (1) and (2),

(A+ B)(A – B) ≠ A2 – B2.

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Chapter 4: Determinants and Matrices - Miscellaneous Exercise 4(B) [Page 102]

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Balbharati Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
Chapter 4 Determinants and Matrices
Miscellaneous Exercise 4(B) | Q II. (17) | Page 102

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