Advertisements
Advertisements
Question
An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0℃ to 15.0℃ in100 s. Calculate:
- the heat capacity of 4.0 kg of liquid,
- the specific heat capacity of the liquid.
Advertisements
Solution
Power of heater P = 600 W
t = 100 S
Mass of liquid m = 4.0 kg
Change in temperature of liquid = (15 − 10)°C = 5°C (or 5 K)
Time taken to raise its temperature = 100 s
(i) Heat capacity of liquid C' = `"Q"/(Δ"T")`
∴ C' = `60000/5`
= 12000 JK-1 or 1.2 × 104 JK-1
(ii) Specific heat capacity of liquid C = ?
C = `"Q"/("m"Δ"T")`
= `60000/(4 xx 5)`
= 3 × 103 J Kg-1°C-1
APPEARS IN
RELATED QUESTIONS
Give three reasons for the increase of green house gases.
Read the following paragraph and answer the questions.
|
If heat is exchanged between a hot and cold object, the temperature of the cold object goes on increasing due to gain of energy and the temperature of the hot object goes on decreasing due to loss of energy. The change in temperature continues till the temperatures of both the objects attain the same value. In this process, the cold object gains heat energy and the hot object loses heat energy. If the system of both the objects is isolated from the environment by keeping it inside a heat resistant box (meaning that the energy exchange takes place between the two objects only), then no energy can flow from inside the box or come into the box. |
- Heat is transferred from where to where?
- Which principle do we learn about from this process?
- How will you state the principle briefly?
- Which property of the substance is measured using this principle?
Define the term 'specific heat capacity' and state its unit.
A liquid X has specific heat capacity higher than the liquid Y. Which liquid is useful as heat reservoir to keep juice bottles without freezing?
An equal quantity of heat is supplied to two substances A and B. The substance A shows a greater rise in temperature. What can you say about the heat capacity of A as compared to that of B?
Solve the following problem.
Specific latent heat of vaporization of water is 2.26 × 106 J/kg. Calculate the energy needed to change 5.0 g of water into steam at 100 ºC.
Numerical Problem.
What is the heat in joules required to raise the temperature of 25 grams of water from 0°C to 100°C? What is the heat in Calories? (Specific heat of water = `(4.18"J")/("g"°"C")`
A diatomic gas undergoes adiabatic change. Its pressure 'P' and temperature 'T' are related as p ∝ Tx, where x is ______.
To study energy exchange between hot and cold objects, the system of both objects is isolated from the environment by keeping them inside ______.
