Advertisements
Advertisements
Question
An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from 10.0℃ to 15.0℃ in100 s. Calculate:
- the heat capacity of 4.0 kg of liquid,
- the specific heat capacity of the liquid.
Advertisements
Solution
Power of heater P = 600 W
t = 100 S
Mass of liquid m = 4.0 kg
Change in temperature of liquid = (15 − 10)°C = 5°C (or 5 K)
Time taken to raise its temperature = 100 s
(i) Heat capacity of liquid C' = `"Q"/(Δ"T")`
∴ C' = `60000/5`
= 12000 JK-1 or 1.2 × 104 JK-1
(ii) Specific heat capacity of liquid C = ?
C = `"Q"/("m"Δ"T")`
= `60000/(4 xx 5)`
= 3 × 103 J Kg-1°C-1
APPEARS IN
RELATED QUESTIONS
You have a choice of three metals A, B, and C, of specific heat capacities 900 Jkg-1 °C-1, 380 Jkg-1 °C-1 and 460 Jkg-1 °C-1 respectively, to make a calorimeter. Which material will you select? Justify your answer.
Discuss the role of high specific heat capacity of water with reference to climate in coastal areas.
Name two green house gases ?
Name the radiations for which the green house gases are opaque ?
What is carbon tax?
Explain, Why is it advisabile to pour cold water over burns, caused on human body, by hot solids?
An electric immersion heater is rated 1250 W. Calculate the time in which it will heat 20 kg of water at 5°C to 65°C.
Calculate the ratio of two specific heats of polyatomic gas molecules.
An office room contains about 4000 moles of air. The change in the internal energy of this much air when it is cooled from 34° C to 19° C at a constant pressure of 1.0 atm is (Use `gamma_"air"` = 1.4 and Universal gas constant = 8.314 J / mol K) ____________.
Calculate the amount of heat energy required to raise the temperature of 200 g of copper from 20°C to 70°C. Specific heat capacity of copper = 390 J kg-1 K-1.
